solve the system of the equation

8x-3y=-22
y=10+4x

1 answer

To solve the system of equations, we want to find the values of x and y that satisfy both equations simultaneously.

We are given:
1) 8x - 3y = -22
2) y = 10 + 4x

We can start by substituting the value of y from the second equation into the first equation:

8x - 3(10 + 4x) = -22
8x - 30 - 12x = -22
-4x - 30 = -22
-4x = 8
x = -2

Now that we have found the value of x, we can substitute it back into the second equation to find the value of y:

y = 10 + 4(-2)
y = 10 - 8
y = 2

Therefore, the solution to the system of equations is x = -2 and y = 2.