To solve the system of equations, we want to find the values of x and y that satisfy both equations simultaneously.
We are given:
1) 8x - 3y = -22
2) y = 10 + 4x
We can start by substituting the value of y from the second equation into the first equation:
8x - 3(10 + 4x) = -22
8x - 30 - 12x = -22
-4x - 30 = -22
-4x = 8
x = -2
Now that we have found the value of x, we can substitute it back into the second equation to find the value of y:
y = 10 + 4(-2)
y = 10 - 8
y = 2
Therefore, the solution to the system of equations is x = -2 and y = 2.
solve the system of the equation
8x-3y=-22
y=10+4x
1 answer