In one equation, solve for one of the variables in terms of the other. For instance,
2x+20y=-144
2x=-144-20y
x=-72-10y
Then plug this variable into the other equation in order to yield a constant for y.
12(-72-10y)+5y=56
-864-120y+5y=56
-864-115y=56
-115y=920
y=-8.
But you're still not done. You have to plug this back into the equation in which you solved for x so you can get a constant value for x as well.
x=-72-10(-8)=-72+80=8
So x=8 and y=-8.
Please try a similiar problem like this on your own so you are able to fully understand how to go about solving systems of equations. This site is here to help you, not do your homework for you. You won't learn anything if you just copied what I just typed up. Learning comes best when cemented independently.
Good luck, and peace out.
solve the system of linear equations using the addition method. Can you please show me the steps on how you reached the answer. Thank You
2x+20y= -144
12x+5y= 56
1 answer