Solve the system of equations x= 6y-3 and2x+7y=13

Answer 1

To solve the system of equations, we can use the method of substitution.

First, we solve the first equation for x:
x = 6y - 3

Next, we substitute this expression for x in the second equation:
2x + 7y = 13
2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1

Now that we know y, we can substitute this value back into the first equation to find x:
x = 6y - 3
x = 6(1) - 3
x = 6 - 3
x = 3

Therefore, the solution to the system of equations is x = 3 and y = 1.