Solve the system of equations. 8x−3y= −22 y=10+4x (1 point)

We can solve this system of equations by substituting the value of y from the second equation into the first equation.

From the second equation, we have y = 10 + 4x.

Substituting this into the first equation:

8x - 3(10 + 4x) = -22.

Now, we can distribute the -3:

8x - 30 - 12x = -22.

Combining like terms, we have:

-4x - 30 = -22.

Adding 30 to both sides:

-4x = 8.

Dividing by -4:

x = -2.

Now that we have the value of x, we can substitute it back into the second equation to find y:

y = 10 + 4(-2).

Simplifying:

y = 10 - 8.

y = 2.

Therefore, the solution to the system of equations is x = -2 and y = 2.

Solve the system of equations. 5x+2y=14 x−6y=22 (1 point)

We can solve this system of equations using the method of elimination or substitution.

Let's use the method of elimination.

First, we multiply the second equation by 5 to match the coefficients of x:

5(x-6y) = 5(22)
5x - 30y = 110

Now, we can subtract the first equation from this new equation:

(5x - 30y) - (5x + 2y) = 110 - 14

Simplifying:

-30y - 2y = 110 - 14
-32y = 96
y = -3

Now, we can substitute the value of y back into one of the original equations. Let's use the first equation:

5x + 2(-3) = 14
5x - 6 = 14
5x = 20
x = 4

Therefore, the solution to the system of equations is x = 4 and y = -3.

Solve the system of equations. –9x+y=12 2x+4y= −28 (1 point)

We can solve this system of equations using the method of substitution.

First, isolate y in the first equation:

-9x + y = 12
y = 9x + 12

Now substitute this expression for y in the second equation:

2x + 4(9x + 12) = -28

Simplify:

2x + 36x + 48 = -28

Combine like terms:

38x + 48 = -28

Subtract 48 from both sides:

38x = -76

Divide by 38:

x = -2

Now substitute the value of x back into the expression for y:

y = 9(-2) + 12
y = -18 + 12
y = -6

Therefore, the solution to the system of equations is x = -2 and y = -6.

To solve the system of equations:

1. Start by substituting the value of y from the second equation into the first equation:

8x - 3(10 + 4x) = -22

2. Simplify the equation by distributing the -3:

8x - 30 - 12x = -22

3. Combine like terms on the left side:

-4x - 30 = -22

4. Add 30 to both sides of the equation:

-4x = -22 + 30

-4x = 8

5. Divide both sides of the equation by -4 to solve for x:

x = 8 / -4

x = -2

6. Now, substitute the value of x into the second equation:

y = 10 + 4(-2)

y = 10 - 8

y = 2

7. Therefore, the solution to the system of equations is x = -2 and y = 2.

To solve the system of equations, we will use the method of substitution. Here's how you can get the solution:

Step 1: Start with the given system of equations:
8x - 3y = -22 ...(Equation 1)
y = 10 + 4x ...(Equation 2)

Step 2: Solve Equation 2 for y by isolating it:
y = 10 + 4x

Step 3: Substitute the value of y from Equation 2 into Equation 1:
8x - 3(10 + 4x) = -22

Step 4: Distribute the -3 to simplify the equation:
8x - 30 - 12x = -22

Step 5: Combine like terms on the left-hand side:
(8x - 12x) - 30 = -22
-4x - 30 = -22

Step 6: Add 30 to both sides of the equation to isolate the variable:
-4x - 30 + 30 = -22 + 30
-4x = 8

Step 7: Divide both sides of the equation by -4 to solve for x:
-4x / -4 = 8 / -4
x = -2

Step 8: Now that we have the value of x, substitute it back into Equation 2 to find the value of y:
y = 10 + 4x
y = 10 + 4(-2)
y = 10 - 8
y = 2

So the solution to the system of equations is x = -2 and y = 2.