Question

Solve the system of equations using with multiplication
4x-6y=-48
-2x+4y=30

Answer 1

To solve the system of equations using multiplication, we can multiply both equations by a constant to eliminate a variable.

Let's start with the second equation:

-2x + 4y = 30

If we multiply this equation by 2, we can eliminate x:

(2)(-2x + 4y) = (2)(30)
-4x + 8y = 60

Now we have:

4x - 6y = -48
-4x + 8y = 60

Adding these two equations together:

(4x - 6y) + (-4x + 8y) = -48 + 60
2y = 12
y = 6

Now, we can substitute this value of y back into one of the original equations to solve for x. Let's use the first equation:

4x - 6(6) = -48
4x - 36 = -48
4x = -48 + 36
4x = -12
x = -12/4
x = -3

Therefore, the solution to the system of equations is x = -3 and y = 6.