To solve this system of equations by substitution, we will first solve one of the equations for one of the variables and then substitute that expression into the other equation.
Let's solve the first equation for y:
14x - 12y = 23x - 6
12y = 9x + 6
y = (9x + 6) / 12
y = (3x + 2) / 4
Now, we substitute this expression for y into the second equation:
P = 23x - 6y
P = 23x - 6(3x + 2) / 4
P = 23x - (18x + 12) / 4
P = 23x - 18x / 4 - 3
P = (23/4)x - 3
Therefore, the solution to the system of equations by substitution is:
P = (23/4)x - 3
solve the system of equations by substitution y 14x − 12y 23x 6
P= _
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