solve the system of equations. -6x + 2y = -32 4x + 3y = -9

Answer 1

To solve this system of equations, we can use the substitution method.

From the first equation, we can isolate y:

-6x + 2y = -32
2y = 6x - 32
y = 3x - 16

Now we substitute y = 3x - 16 into the second equation:

4x + 3(3x - 16) = -9
4x + 9x - 48 = -9
13x - 48 = -9
13x = 39
x = 3

Now that we have found the value of x, we can substitute it back into y = 3x - 16 to find y:

y = 3(3) - 16
y = 9 - 16
y = -7

Therefore, the solution to the system of equations is x = 3, y = -7.

Answer 2

are you sure

Answer 3

Let's double-check the solution by substituting x = 3 and y = -7 back into the original equations:

1. -6x + 2y = -32
-6(3) + 2(-7) = -32
-18 - 14 = -32
-32 = -32

2. 4x + 3y = -9
4(3) + 3(-7) = -9
12 - 21 = -9
-9 = -9

Since the solutions x = 3 and y = -7 satisfy both equations, the solution is correct. The system of equations is solved.