Asked by dj
Solve the system of equations.
y = 2x² – 3
y = 3x – 1
A. no solution
B. (–one-half, 5), (2, –start fraction 5 over 2 end fraction)
C. (–one-half, –start fraction 5 over 2 end fraction), (2, 5)
D. (one-half, start fraction 5 over 2 end fraction), (2, 5)
y = 2x² – 3
y = 3x – 1
A. no solution
B. (–one-half, 5), (2, –start fraction 5 over 2 end fraction)
C. (–one-half, –start fraction 5 over 2 end fraction), (2, 5)
D. (one-half, start fraction 5 over 2 end fraction), (2, 5)
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
2x² – 3 = 3x – 1
2x² - 3x - 2 = 0
(2x+1)(x-2) = 0
x = -1/2, 2
2x² – 3 = 3x – 1
2x² - 3x - 2 = 0
(2x+1)(x-2) = 0
x = -1/2, 2
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