Solve the system of equations. 3x−4y%3D40 5x−5y%3D55 (1 point) Responses (8%2C−3) left parenthesis 8 comma negative 3 right parenthesis (14%2C 3) left parenthesis 14 comma 3 right parenthesis (18%2C 7) left parenthesis 18 comma 7 right parenthesis (4%2C−7)

Answer 1

To solve the system of equations, we can use the method of substitution or elimination.

Let's solve it using the method of substitution:
From the first equation, we have: 3x - 4y = 40 ----(1)
Solve this equation for x:
3x = 4y + 40
x = (4y + 40)/3 ----(2)

Substitute x in the second equation with the expression (4y + 40)/3:
5(4y + 40)/3 - 5y = 55
5(4y + 40) - 15y = 165
20y + 200 - 15y = 165
5y + 200 = 165
5y = -35
y = -7

Now, substitute the value of y in equation (2):
x = (4(-7) + 40)/3
x = (28 + 40)/3
x = 68/3
x = 22.67

Therefore, the solution to the system of equations is (22.67, -7).