Solve the system of equations.%0D%0A3x−4y=40%0D%0A5x−5y=55(1 point

1 answer

To solve the system of equations, we can use the method of substitution or elimination.

Let's solve it using the method of substitution.

From the first equation, we have:
3x - 4y = 40

Solving for x, we get:
3x = 4y + 40
x = (4y + 40)/3

Now we substitute this value of x into the second equation:
5x - 5y = 55
5((4y + 40)/3) - 5y = 55
(20y + 200)/3 - 5y = 55
(20y + 200) - 15y = 165
20y - 15y = 165 - 200
5y = -35
y = -7

Now substituting the value of y back into the first equation to find x:
3x - 4(-7) = 40
3x + 28 = 40
3x = 40 - 28
3x = 12
x = 4

Therefore, the solution to the system of equations is x = 4 and y = -7.