Asked by crystal
solve the system of equation for all variables using a matix
x-y-z=1
2x-3y+z=10
x+y-2z=0
x-y-z=1
2x-3y+z=10
x+y-2z=0
Answers
Answered by
Reiny
form the augmented matrix
1 -1 -1 1
2 -3 1 0
1 2 -2 0
=
1 -1 -1 1
0 1 -3 -8 I did 2x#1 - #2
0 -2 1 1 I did #1 - #1
=
1 -1 -1 1
0 1 -3 -8
0 0 -5 -15 I did 2x#2 - #3
=
1 -1 -1 1
0 1 -3 -8
0 0 1 3
At this point you can work backwards since the last line says
z = 3
put that back into line 2, which says
y - 3z = -8
etc
1 -1 -1 1
2 -3 1 0
1 2 -2 0
=
1 -1 -1 1
0 1 -3 -8 I did 2x#1 - #2
0 -2 1 1 I did #1 - #1
=
1 -1 -1 1
0 1 -3 -8
0 0 -5 -15 I did 2x#2 - #3
=
1 -1 -1 1
0 1 -3 -8
0 0 1 3
At this point you can work backwards since the last line says
z = 3
put that back into line 2, which says
y - 3z = -8
etc
Answered by
Reiny
Another way:
If you know how to find the inverse of a 3x3 matrix, find it, then multiply that inverse matrix by the column matrix
1
10
0
here is how to find the inverse of a 3x3 matrix, this is the method I use.
http://www.wikihow.com/Inverse-a-3X3-Matrix
If you know how to find the inverse of a 3x3 matrix, find it, then multiply that inverse matrix by the column matrix
1
10
0
here is how to find the inverse of a 3x3 matrix, this is the method I use.
http://www.wikihow.com/Inverse-a-3X3-Matrix
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