To solve the system of equations, we can use the method of substitution.
First, solve one equation for x or y, and substitute the expression into the other equation.
From the first equation, we can solve for x:
4x - 6y = -48
4x = 6y - 48
x = (6y - 48)/4
x = (3/2)y - 12
Now substitute this expression for x into the second equation:
-2x + 4y = 30
-2((3/2)y - 12) + 4y = 30
-3y + 24 + 4y = 30
y + 24 = 30
y = 6
Now substitute this value of y back into either of the original equations to solve for x:
4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3
Therefore, the solution to the system of equations is x = -3 and y = 6.
Solve the system equations
4x-6y=-48
-2x+4y=30
1 answer