Solve the system by elimination.

Question

3x−3y=1
x−y=15

Answer 1

To solve the system by elimination, we can multiply the second equation by 3 to make the coefficients of x in both equations the same.

Original system:
3x − 3y = 1
x − y = 15

Multiply the second equation by 3:
3(x − y) = 3(15)
3x − 3y = 45

Now the system becomes:
3x − 3y = 1
3x − 3y = 45

Subtract the first equation from the second equation:
(3x − 3y) − (3x − 3y) = 45 − 1
0 = 44

This equation is contradictory and cannot be true. Therefore, the system is inconsistent and has no solution.