Ask a New Question

Solve the poloynomial

x^3+4x^2-x-4=0

1 answer

x^3+4x^2-x-4=0

use grouping

x^2(x+4) - (x+4) = 0
(x+4)(x^2 - 1) = 0
(x+4)(x+1)(x-1) = 0

x = -4, ± 1

Ask a New Question or answer this question.

Similar Questions

Solve the poloynomialx^3+4x^2-x-4=0
1. 1 answer
First: solve for k. Then, go back to the original equation c=k(d-3) and solve for c when d is ten.Second: Area=k*s^2 Put in the
1. 1 answer
Combine like terms:-3x^2+2x-4x^2-9+6x-2x^2+8 Solve for x: 8x-11= -11x+18 Solve for x: -2(x-5)+7=z-8-5x Solve for x: (x-2)/5 -
1. 8 answers
Solve the indicated variable:1. Volume of a cone: solve for h: V=¨ir^2h/3 2. Temperature formula: solve for C: F=9/5C+32
1. 1 answer

more similar questions