Solve the inequality x^2(8+x)(x-9)/(x+4)(x-7) is greater than or equal to 0?

Answer 1

x^2(8+x)(x-9)/(x+4)(x-7) >=0
x^2(8+x)(x-9)(x+4)(x-7)>=0
therefore the ranges are x>=9,0<=x<=7,-8<=x<=-4
But x cannot equal -4 or 7
therefore the ranges of x are
x>=9,0<=x<7,-8<=x<-4

Answer 2

Hmm. I get
x in (-oo,-8] U [-4,7] U (9,+oo)
Gotta watch to be sure top and bottom are same sign.