|x+3| + 8 <= 14,
|x+3| <= 6,
+-(x+3)<= 6,
+(x+3) <= 6,
x+3 >= 6,
X <= 6-3,
X <= 3.
-(x+3) <= 6,
-x - 3 <= 6,
-x <= 6+3,
-x <= 9,
X >= -9.
Solution set: -9 =< X <= 3.
Intrval notation: [-9,3].
Solve the inequality by first rewriting it as an equivalent inequality without absolute value bars. Express solution set using interval notation.
| x+3 | +8 is less than or equal to 14
Thanks so much for helping me!
1 answer