To solve the inequality 5(2k−3)≥−3(4−3k), we follow these steps:

Question

1. **Distribute**:
- Left: $5(2k)-5(3)=10k-15$
- Right: $-3(4)+9k=-12+9k$

Now, rewriting the inequality:
$$10k-15\ge -12+9k$$

2. **Combine like terms**:
Subtract $9k$ from both sides:
$$10k-9k-15\ge -12$$
This simplifies to:
$$k-15\ge -12$$

3. **Isolate $k$**:
Add 15 to both sides:
$$k\ge 3$$

Thus, the solution is:
$$k\ge 3$$make this smaller

Answer 1

To solve the inequality $5(2k-3)\ge -3(4-3k)$, we can follow these concise steps:

1. Distribute:

   • Left: $5(2k)-5(3)=10k-15$
   • Right: $-3(4)+9k=-12+9k$

   Rewrite the inequality: $$10k-15\ge -12+9k$$

2. Combine like terms: Subtract $9k$ from both sides: $$10k-9k-15\ge -12$$ Simplifying gives: $$k-15\ge -12$$

3. Isolate $k$: Add 15 to both sides: $$k\ge 3$$

Thus, the solution is: $$k\ge 3$$