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Solve the inequality and graph the solution. v+1 3 ≥ – 1 Plot the endpoints. Select an endpoint to change it from closed to ope...Asked by evergreen
Solve the inequality and graph the solution.
1>f–7
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
1>f–7
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
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Answered by
GPT-4o mini
To solve the inequality \( 1 > f - 7 \), we can first rearrange it:
\[
1 + 7 > f
\]
\[
8 > f
\]
or alternatively,
\[
f < 8
\]
This means that \( f \) can take any value less than 8.
### Graphing the Solution
1. **Endpoints**: The endpoint of our solution is \( f = 8 \).
2. **Closed or Open**: Since \( f \) must be less than 8 and not equal to it, we use an open circle at \( f = 8 \) to indicate that 8 is not included in the solution.
3. **Deleting the middle**: Since \( f < 8 \) means all numbers less than 8, we will graph this on a number line.
### Graph Representation:
- Draw a number line.
- Place an open circle at \( 8 \) to show that it's not included.
- Shade to the left of \( 8 \) to represent all values less than 8.
```
<---o=========================>
8
```
Here, "o" indicates an open circle at \( 8 \) and the line shaded to the left shows all numbers that satisfy the inequality \( f < 8 \).
\[
1 + 7 > f
\]
\[
8 > f
\]
or alternatively,
\[
f < 8
\]
This means that \( f \) can take any value less than 8.
### Graphing the Solution
1. **Endpoints**: The endpoint of our solution is \( f = 8 \).
2. **Closed or Open**: Since \( f \) must be less than 8 and not equal to it, we use an open circle at \( f = 8 \) to indicate that 8 is not included in the solution.
3. **Deleting the middle**: Since \( f < 8 \) means all numbers less than 8, we will graph this on a number line.
### Graph Representation:
- Draw a number line.
- Place an open circle at \( 8 \) to show that it's not included.
- Shade to the left of \( 8 \) to represent all values less than 8.
```
<---o=========================>
8
```
Here, "o" indicates an open circle at \( 8 \) and the line shaded to the left shows all numbers that satisfy the inequality \( f < 8 \).
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