To solve the inequality
\[ \frac{v + 1}{3} \geq -1, \]
we start by isolating \( v \).
- Multiply both sides of the inequality by 3 to eliminate the fraction (note that since 3 is positive, the direction of the inequality does not change):
\[ v + 1 \geq -3. \]
- Next, subtract 1 from both sides:
\[ v \geq -4. \]
Now, we have the solution to the inequality, which is
\[ v \geq -4. \]
Graphing the Solution:
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Plot the endpoint at \( v = -4 \). Since the inequality includes \( \geq \), we will use a closed dot on -4 to indicate that -4 is included in the solution set.
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Draw a ray extending to the right from -4 to indicate that all values greater than -4 are included in the solution.
Final Graph Summary:
- Closed dot at \( -4 \)
- Shade the line to the right of -4.
This represents all values \( v \) such that \( v \) is greater than or equal to -4.