To find the change in temperature over the three-hour period from 9 AM to noon, we can set up the problem as follows:
Let:
- \( T_1 \) = temperature at 9 AM = -5.8°C
- \( T_2 \) = temperature at noon = -1.6°C
The change in temperature (\( \Delta T \)) can be calculated using the formula:
\[ \Delta T = T_2 - T_1 \]
Substituting in the values:
\[ \Delta T = -1.6 - (-5.8) \]
When you subtract a negative number, it is equivalent to addition:
\[ \Delta T = -1.6 + 5.8 \]
Now performing the addition:
\[ \Delta T = 4.2 \]
Thus, the change in temperature from 9 AM to noon is \( 4.2°C \).
Explanation:
This positive change in temperature indicates that the air temperature increased by \( 4.2°C \) during the three-hour period from 9 AM to noon. Despite both temperatures being below freezing (negative), this increase shows a rising trend in temperature, which could result from various factors such as increased sunlight or changing weather conditions.