To find the change in temperature during the three hours from 9 AM to noon, we need to subtract the initial temperature from the final temperature.
The initial temperature at 9 AM is -5.8°C, and the final temperature at noon is -1.6°C. Subtracting the initial temperature from the final temperature gives us:
-1.6°C - (-5.8°C) = -1.6°C + 5.8°C = 4.2°C
So, the change in temperature during these three hours is 4.2°C.
The equation to represent this change in temperature is:
Final temperature - Initial temperature = Change in temperature
Let T be the final temperature, T0 be the initial temperature, and ΔT be the change in temperature. The equation becomes:
T - T0 = ΔT
In this case, T = -1.6°C, T0 = -5.8°C, and ΔT = 4.2°C.
Substituting these values into the equation, we have:
-1.6°C - (-5.8°C) = 4.2°C
Simplifying the equation further, we get:
-1.6°C + 5.8°C = 4.2°C
Therefore, the equation -1.6°C + 5.8°C = 4.2°C represents the change in temperature during the three hours from 9 AM to noon. It means that the temperature increased by 4.2°C during that time period.
Solve the following word problem the air temperature at 9 AM is -5.8°C. Is there a temperature at noon is -1.6°C. What is the changing the temperature during these three hours right and solve an equation to show your answer, then explain your answer means.
1 answer