To solve the system of equations using the elimination method, we start with the following equations:
- \( 3x - 4y = -4 \) (Equation 1)
- \( x + 3y = -10 \) (Equation 2)
Step 1: Align equations
We will eliminate one variable by aligning the equations. Let's express them in a suitable form for elimination.
Multiply Equation 2 by 3 to align with the coefficient of \(x\) in Equation 1:
\[ 3(x + 3y) = 3(-10) \]
This gives us:
\[ 3x + 9y = -30 \quad \text{(Equation 3)} \]
Step 2: Set up for elimination
Now, we have:
- \( 3x - 4y = -4 \) (Equation 1)
- \( 3x + 9y = -30 \) (Equation 3)
Step 3: Eliminate \(x\)
Subtract Equation 1 from Equation 3:
\[ (3x + 9y) - (3x - 4y) = -30 - (-4) \]
This simplifies to:
\[ 9y + 4y = -30 + 4 \]
Combining like terms:
\[ 13y = -26 \]
Step 4: Solve for \(y\)
Now, divide by 13:
\[ y = -2 \]
Step 5: Substitute \(y\) back to solve for \(x\)
Substituting \(y = -2\) back into Equation 2:
\[ x + 3(-2) = -10 \] \[ x - 6 = -10 \] \[ x = -10 + 6 \] \[ x = -4 \]
Final Solution
The solution to the system of equations is \( (x, y) = (-4, -2) \).
Thus, the correct answer is:
\[ \boxed{(-4, -2)} \]