Asked by Christopher
Solve the following simultaneous linear and quadratic equations
x=y; 2x^2-y^=1
x=y; 2x^2-y^=1
Answers
Answered by
Reiny
just replace y with x, since it says y = x
2x^2 - x^2 = 1
x^2 = 1
x = ±1
if x = 1, then y = 1
if x = -1, then y = -1
2x^2 - x^2 = 1
x^2 = 1
x = ±1
if x = 1, then y = 1
if x = -1, then y = -1
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