Asked by Anonymous
Solve the following simultaneous equation by substitution method 5x+y=35 & 3x-2y=14
Answers
Answered by
Bosnian
5 x + y = 35 Subtact 5 x to both sides
5 x + y - 5 x = 35 - 5 x
y = 35 - 5 x
3 x - 2 y = 14
3 x - 2 ( 35 - 5 x ) = 14
3 x - 2 * 35 - 2 * ( - 5 x ) = 14
3 x - 70 + 10 x = 14
13 x - 70 = 14 Add 70 to bopth sides
13 x - 70 + 70 = 14 + 70
13 x = 84 Divide both sides by 13
13 x / 13 = 84 / 13
x = 84 / 13
y = 35 - 5 x
y = 35 - 5 * 84 / 13
y = 35 - 420 / 13
y = 35 * 13 / 13 - 420 /13
y = 455 / 13 - 420 / 13
y = 35 / 13
Solution:
x = 84 / 13 , y = 35 / 13
5 x + y - 5 x = 35 - 5 x
y = 35 - 5 x
3 x - 2 y = 14
3 x - 2 ( 35 - 5 x ) = 14
3 x - 2 * 35 - 2 * ( - 5 x ) = 14
3 x - 70 + 10 x = 14
13 x - 70 = 14 Add 70 to bopth sides
13 x - 70 + 70 = 14 + 70
13 x = 84 Divide both sides by 13
13 x / 13 = 84 / 13
x = 84 / 13
y = 35 - 5 x
y = 35 - 5 * 84 / 13
y = 35 - 420 / 13
y = 35 * 13 / 13 - 420 /13
y = 455 / 13 - 420 / 13
y = 35 / 13
Solution:
x = 84 / 13 , y = 35 / 13
Answered by
usman basit
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