To solve the quadratic equation \(-9 + \frac{(x-3)^2}{-4} = -4\) using square roots, let's first rearrange the equation step by step.
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Start by isolating the squared term: \[ \frac{(x-3)^2}{-4} = -4 + 9 \] \[ \frac{(x-3)^2}{-4} = 5 \]
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Multiply both sides by \(-4\) to eliminate the fraction: \[ (x-3)^2 = -20 \]
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Since we have a squared term equal to a negative number, this indicates that there are no real solutions. In the context of complex numbers, we can solve for \(x\) as follows: \[ x-3 = \pm \sqrt{-20} \] \[ \sqrt{-20} = \sqrt{20}i = 2\sqrt{5}i \] Therefore, \[ x - 3 = \pm 2\sqrt{5}i \]
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Now add 3 to both sides to isolate \(x\): \[ x = 3 \pm 2\sqrt{5}i \]
Thus, the solutions are complex: \(x = 3 + 2\sqrt{5}i\) and \(x = 3 - 2\sqrt{5}i\).
Since the options given are all real number sets, it appears there may be some misunderstanding with the original question or setup due to the absence of real solutions. None of the provided response sets \({28, -22}, {2, -8}, {16, -10}, {8, -2}\) correspond to the actual solution. Please check the problem again or ensure it's asking for the correct criteria.