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Solve the following quadratic equation using square roots. Round to the nearest hundredth if necessary: (x−6)^2=51.(1 point)Asked by skibibi
Solve the following quadratic equation using square roots. Round to the nearest hundredth if necessary: (x+27)2−6=−3.(1 point)
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Answered by
GPT-4o mini
To solve the quadratic equation \((x + 27)^2 - 6 = -3\), we'll follow these steps:
1. **Isolate the squared term**: Start by adding 6 to both sides of the equation.
\[
(x + 27)^2 - 6 + 6 = -3 + 6
\]
\[
(x + 27)^2 = 3
\]
2. **Take the square root of both sides**: When taking the square root, remember to include both the positive and negative roots.
\[
x + 27 = \sqrt{3} \quad \text{or} \quad x + 27 = -\sqrt{3}
\]
3. **Solve for \(x\)**: Subtract 27 from both sides for both cases.
For \(x + 27 = \sqrt{3}\):
\[
x = \sqrt{3} - 27
\]
For \(x + 27 = -\sqrt{3}\):
\[
x = -\sqrt{3} - 27
\]
4. **Calculate the numerical values**: Using the approximation \(\sqrt{3} \approx 1.732\):
- For \(x = \sqrt{3} - 27\):
\[
x \approx 1.732 - 27 \approx -25.268
\]
- For \(x = -\sqrt{3} - 27\):
\[
x \approx -1.732 - 27 \approx -28.732
\]
5. **Round the results to the nearest hundredth**:
- First solution: \(x \approx -25.27\)
- Second solution: \(x \approx -28.73\)
Thus, the solutions to the quadratic equation are:
\[
x \approx -25.27 \quad \text{and} \quad x \approx -28.73
\]
1. **Isolate the squared term**: Start by adding 6 to both sides of the equation.
\[
(x + 27)^2 - 6 + 6 = -3 + 6
\]
\[
(x + 27)^2 = 3
\]
2. **Take the square root of both sides**: When taking the square root, remember to include both the positive and negative roots.
\[
x + 27 = \sqrt{3} \quad \text{or} \quad x + 27 = -\sqrt{3}
\]
3. **Solve for \(x\)**: Subtract 27 from both sides for both cases.
For \(x + 27 = \sqrt{3}\):
\[
x = \sqrt{3} - 27
\]
For \(x + 27 = -\sqrt{3}\):
\[
x = -\sqrt{3} - 27
\]
4. **Calculate the numerical values**: Using the approximation \(\sqrt{3} \approx 1.732\):
- For \(x = \sqrt{3} - 27\):
\[
x \approx 1.732 - 27 \approx -25.268
\]
- For \(x = -\sqrt{3} - 27\):
\[
x \approx -1.732 - 27 \approx -28.732
\]
5. **Round the results to the nearest hundredth**:
- First solution: \(x \approx -25.27\)
- Second solution: \(x \approx -28.73\)
Thus, the solutions to the quadratic equation are:
\[
x \approx -25.27 \quad \text{and} \quad x \approx -28.73
\]
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