Solve the following quadratic equation using square roots. Round to the nearest hundredth if necessary: (x+16)29=7

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1 answer

To solve the equation \((x + 16)29 = 7\), we first need to isolate the term involving \(x\).

  1. Divide both sides of the equation by 29:

\[ x + 16 = \frac{7}{29} \]

  1. Next, we isolate \(x\) by subtracting 16 from both sides:

\[ x = \frac{7}{29} - 16 \]

  1. To combine \(\frac{7}{29}\) and \(-16\), we can convert \(-16\) into a fraction with a denominator of 29:

\[ -16 = -\frac{16 \times 29}{29} = -\frac{464}{29} \]

  1. Now, substituting this back into our equation gives:

\[ x = \frac{7}{29} - \frac{464}{29} \]

  1. This simplifies to:

\[ x = \frac{7 - 464}{29} = \frac{-457}{29} \]

  1. Finally, calculating \(-457 \div 29\):

\[ x \approx -15.762068965517241 \]

Rounding to the nearest hundredth, we get:

\[ x \approx -15.76 \]

Thus, the solution to the equation is

\[ \boxed{-15.76} \]