Solve the following quadratic equation for all values of xx in simplest form.

4, left parenthesis, x, squared, plus, 5, right parenthesis, minus, 17, equals, 12
4(x
2
+5)−17=
12

1 answer

To solve the given quadratic equation, we start with:

\[ 4(x^2 + 5) - 17 = 12. \]

First, let's simplify the left side of the equation:

  1. Distribute the 4: \[ 4x^2 + 20 - 17 = 12. \]

  2. Combine the constant terms (20 and -17): \[ 4x^2 + 3 = 12. \]

Next, we need to isolate the \(x^2\) term:

  1. Subtract 3 from both sides: \[ 4x^2 = 12 - 3, \] which simplifies to: \[ 4x^2 = 9. \]

  2. Now, divide both sides by 4: \[ x^2 = \frac{9}{4}. \]

  3. To find \(x\), take the square root of both sides: \[ x = \pm \sqrt{\frac{9}{4}}. \]

The square root of a fraction can be simplified: \[ x = \pm \frac{\sqrt{9}}{\sqrt{4}} = \pm \frac{3}{2}. \]

Thus, the solutions for \(x\) are: \[ x = \frac{3}{2} \quad \text{and} \quad x = -\frac{3}{2}. \]

In conclusion, the values of \(x\) in simplest form are: \[ \boxed{\frac{3}{2} \text{ and } -\frac{3}{2}}. \]