A
x = 0 is a solution
also
sin x = 2 cos x
is
tan x = 2
that happens at x = 63.4 degrees and at x = 243.4 degrees
convert those to radians by multiplying by pi/180
Solve the following equations for 0 < x < 2pi
A) sin^2x=2sinxcosx
B) 3tanx=cosx
Please help
Thankyou
2 answers
B
3 (sin x/ cos x) = cos x
3 sin x = cos^2 x
3 sin x = (1 - sin^2 x)
sin^2 x + sin x -1 = 0
let z = sin x
z^2 + z - 1 = 0
z = [ -1 +/- sqrt (1+4) ]/2
z = [-1 +/- 2.24 ]/2
z = sin x = .618 or something too big to be a sin of anything
3 (sin x/ cos x) = cos x
3 sin x = cos^2 x
3 sin x = (1 - sin^2 x)
sin^2 x + sin x -1 = 0
let z = sin x
z^2 + z - 1 = 0
z = [ -1 +/- sqrt (1+4) ]/2
z = [-1 +/- 2.24 ]/2
z = sin x = .618 or something too big to be a sin of anything
1 answer