sin r = cos(r+20)
sin r = cos r cos 20 + sin r sin 20
sin r = cos r cos 20 + sin2 r sin 20
sin r - sin2 r sin 20 = cos r cos 20
sin r (1 - sin 20) = cos r cos 20
sin r = cos r cos 20 / (1 - sin 20)
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20 + 2nπ
where n is an integer.
Solve the following equation:
Sin r =cos(r+20)
With shown working below
4 answers
sin r = cos(r+20)
sin r = cos r cos 20 + sin r sin 20
sin r = cos r cos 20 + sin2 r sin 20
sin r - sin2 r sin 20 = cos r cos 20
sin r (1 - sin 20) = cos r cos 20
sin r = cos r cos 20 / (1 - sin 20)
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20 + 2nπ
where n is an integer.
sin r = cos r cos 20 + sin r sin 20
sin r = cos r cos 20 + sin2 r sin 20
sin r - sin2 r sin 20 = cos r cos 20
sin r (1 - sin 20) = cos r cos 20
sin r = cos r cos 20 / (1 - sin 20)
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20 + 2nπ
where n is an integer.
Solve the following equation:
Sin r =cos(r+20)
With shown working below
asked by Mildred Oshio
just now
2 answers
sin r = cos(r+20)
sin r = cos r cos 20 + sin r sin 20
sin r = cos r cos 20 + sin2 r sin 20
sin r - sin2 r sin 20 = cos r cos 20
sin r (1 - sin 20) = cos r cos 20
sin r = cos r cos 20 / (1 - sin 20)
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20 + 2nπ
where n is an integer.
answered
just now
sin r = cos(r+20)
sin r = cos r cos 20 + sin r sin 20
sin r = cos r cos 20 + sin2 r sin 20
sin r - sin2 r sin 20 = cos r cos 20
sin r (1 - sin 20) = cos r cos 20
sin r = cos r cos 20 / (1 - sin 20)
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20 + 2nπ
where n is an integer.
Sin r =cos(r+20)
With shown working below
asked by Mildred Oshio
just now
2 answers
sin r = cos(r+20)
sin r = cos r cos 20 + sin r sin 20
sin r = cos r cos 20 + sin2 r sin 20
sin r - sin2 r sin 20 = cos r cos 20
sin r (1 - sin 20) = cos r cos 20
sin r = cos r cos 20 / (1 - sin 20)
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20 + 2nπ
where n is an integer.
answered
just now
sin r = cos(r+20)
sin r = cos r cos 20 + sin r sin 20
sin r = cos r cos 20 + sin2 r sin 20
sin r - sin2 r sin 20 = cos r cos 20
sin r (1 - sin 20) = cos r cos 20
sin r = cos r cos 20 / (1 - sin 20)
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20
r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20 + 2nπ
where n is an integer.
AAAaannndd the bot gets it wrong yet again!
Assuming degrees, we have
since cosx = sin(90-x)
r + r+20 = 90
r = 35
check: sin35° = cos55° ✅
there are other solutions in QIII, but judging from the simplicity of the question, I suspect we need only use QI.
Assuming degrees, we have
since cosx = sin(90-x)
r + r+20 = 90
r = 35
check: sin35° = cos55° ✅
there are other solutions in QIII, but judging from the simplicity of the question, I suspect we need only use QI.