Ask a New Question
Search
Questions and answers by
Mildred Oshio
Questions (6)
Solve the following equation:
Sin r =cos(r+20) With shown working below
4 answers
113 views
If the root of the equation X square - kx + 42 =0 with shown working below
3 answers
136 views
Find the quadratic equation whose roots are given -2/3 and -1/4 with shown working below
3 answers
144 views
Factorize 8n square=49n+75 with shown working below
2 answers
94 views
Factorize 8n square=49n+75 with shown working
0 answers
115 views
50 students were asked what they did last night 16 said they read a book 41 said they watched television. If 7 said they did
1 answer
151 views
Answers (5)
Solve the following equation: Sin r =cos(r+20) With shown working below asked by Mildred Oshio just now 2 answers sin r = cos(r+20) sin r = cos r cos 20 + sin r sin 20 sin r = cos r cos 20 + sin2 r sin 20 sin r - sin2 r sin 20 = cos r cos 20 sin r (1 - sin
sin r = cos(r+20) sin r = cos r cos 20 + sin r sin 20 sin r = cos r cos 20 + sin2 r sin 20 sin r - sin2 r sin 20 = cos r cos 20 sin r (1 - sin 20) = cos r cos 20 sin r = cos r cos 20 / (1 - sin 20) r = cos-1 (cos r cos 20 / (1 - sin 20)) - 20 r = cos-1
X^2 - kx + 42 = 0 (X - 7)(X - 6) = 0 X = 7 or X = 6 The answer is X = 7 or X = 6.
The quadratic equation is given by ax^2 + bx + c = 0, where a, b and c are constants. We can use the formula for finding the quadratic equation given the roots: a = 1, b = (root1 + root2), c = root1 * root2 Therefore, the quadratic equation is: x^2 + (
8n² = 49n + 75 8n² - 49n = 75 8n² - 49n - 75 = 0 (8n - 25)(n + 3) = 0 8n - 25 = 0 n = 25/8 n + 3 = 0 n = -3
