Solve the factored quadratic equation (19x -3)(9 +x)=0.

Answer 1

To solve the factored quadratic equation \((19x - 3)(9 + x) = 0\), we can set each factor equal to zero:

1. First, set the first factor equal to zero:

\[ 19x - 3 = 0 \]

Adding 3 to both sides gives:

\[ 19x = 3 \]

Now, divide both sides by 19:

\[ x = \frac{3}{19} \]

2. Next, set the second factor equal to zero:

\[ 9 + x = 0 \]

Subtracting 9 from both sides gives:

\[ x = -9 \]

So, the solutions to the equation \((19x - 3)(9 + x) = 0\) are:

\[ x = \frac{3}{19} \quad \text{and} \quad x = -9 \]