I assume you meant
4^(x-3) = 32^x
Since 4=2^2 and 32=2^5, we have
2^(2x-6) = 2^(5x)
2x-6 = 5x
3x = -6
x = -2
Check: 4^(-5) = 2^-10
32^(-2) = 2^-10
Solve the exponential equation using logarithms. Give the answer in decimal form, rounding to four decimal places. (Enter your answers as a comma-separated list.)
4x − 3 = 32x
x = _____
2 answers
no it looks more like this:
4^(x-3)=3^2x
4^(x-3)=3^2x