well, log_2(n) = 2log_4(n), so you have
log_4(3x+4) = 2log_4(2x+1)
3x+4 = (2x+1)^2
4x^2 + x - 3 = 0
(4x-3)(x+1) = 0
x = 3/4 or -1
But x = -1 does not fit the original equation.
solve the equation log of base 4 (3x+4) = log of base two (2x+1)
1 answer
1 answer