raise 1/6 to the power
(x^2+x)/(x^2-x) = (1/6)^-2 = 36
(x+1)/(x-1) = 36
x = 37/35
Solve the equation
log[1/6](x^2+x)-log[1/6](x^2-x)=-2
1 answer
log[1/6](x^2+x)-log[1/6](x^2-x)=-2
1 answer
2 answers
4 answers
1 answer
1 answer