Solve the equation in the interval [0, 2pi].

2sin(t)cos(t)-cos(t)+2sin(t)-1=0

Answer needs to be formatted as x={Insert answers here}pi

If the answer is something like pi/6 it simply goes in as 1/6th since pi is already given at the end.

1 answer

2sin(t)cos(t)-cos(t)+2sin(t)-1=0
cost(2sint - 1) + (2sint - 1) = 0
(2sint - 1)(cost + 1) = 0
sint = 1/2 or cost = -1

if sint = 1/2
t = π/6 or t = 5π/6

if cost = -1, look at your cosine curve,
t = π
Similar Questions
  1. 2sin(x)cos(x)+cos(x)=0I'm looking for exact value solutions in [0, 3π] So I need to find general solutions to solve the
    1. answers icon 6 answers
  2. Solve the equation on the interval [0,2pi).2sin^2x-3sinx+1=0 (2sinx+1)(sinx+1) I don't think I did the factoring correctly. When
    1. answers icon 2 answers
  3. For the trig equation: 2sin(x)tan(x) = tan(x),Why can't I just divide both sides by tan(x) and be left to solve only 2sin(x)=1?
    1. answers icon 3 answers
  4. y= 2sin^2 xy=1- sinx find values of x inthe interval 0<x<360 if 2sin^x = 1-sinx this can be arranged into the quadratic. 2sin^2
    1. answers icon 0 answers
more similar questions