Solve the equation. If necessary, round to thousandths.
3^(2x + 1) = 27
3 answers
my bad supposed to say algebra 2
3^(2x+1) = 3^3
2x+1 = 3
2x=2
x=1
2x+1 = 3
2x=2
x=1
Substitute (2x + 1) for y.
3^y = 27
y = 3
Back-substitute.
2x + 1 = 3
x = 1
3^y = 27
y = 3
Back-substitute.
2x + 1 = 3
x = 1
2 answers