solve the equation for the range zero degrees less than or equal to theta less than or equal to 360 degrees.

Question

4 sin 0=-1

Answer 1

4sinØ = -1, 0° ≤ Ø ≤ 360°

sinØ = -1/4
my calculator gives me Ø = -14.48°
but that is outside our domain

Here is how I do those types:
Since sinØ is negative, I know that my angle Ø must be in quadrants III or IV
so I use sinØ = +1/4 to get +14.48°

in quad III we have 180+14.48 = 194.48°
in quad IV we have 360-14.48 = 345.52°

check these answers with your calculator, they both work
Also notice that -14.48° is co-terminal with 345.52°,
your calculator is programmed to give you the angle closest to zero , which would be -14.48°

Answer 2

I wanted to help u by solving this question..
So, first of all we need to do is... understand the question & then i literally dont know the solution #wasted