Recall that
1-cos theta/ sin theta = tan(theta/2)
so, we want tan(theta/2) = sqrt(3)
theta/2 = 60
theta = 120
Note that theta/2 = 240 also works, but that requires theta=480, outside the domain given.
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2cos^2(2x) - 1 + cos(2x) = 0
(2cos2x - 1)(cos2x + 1) = 0
cos2x = 1/2, so 2x = 60,300, so x=30,150
cos2x = -1, so 2x = 180, so x=90
Solve the equation in the given Domain:
1-cos theta/ sin theta = sqr3, 0degrees <or equal to theta < 369 degrees
cos4x + cos 2x =0, 0<or equal to x < pi
1 answer
1 answer