Ask a New Question
Menu

Solve the equation for all values of x.

-2cos²x-sin x+1=0, on the interval [0,2π).

1 answer

-(2cosx-1)(cosx+1) = 0
so, where is cosx = 1/2 or -1?
Similar Questions
  1. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
    1. answers icon 4 answers
  2. 2cos2x=-sinxsolve for x over the interval [-pi,+pi] x= 0.6349radians x=2.507radians x= 1.003 radians x= 2.138 radians
    1. answers icon 10 answers
  3. Solve the equation 2cos2x = √3 for 0°≤x≤360°I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct?
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions