sqrt(3-x) = x-1.
Start by squaring both sides.
3 - x = x^2 - 2x + 1
0 = x^2 - x - 2
Factor the equation:
0 = (x-2)(x+1)
So x = 2 or x = 1
Solve the equation. Check all proposed solutions. Show work in solving and in checking.
Root3-x = x-1
5 answers
you made a mistake it is x=2 or x=1 its x=2 or x=-1
I am still confused. Can someone please explain further and break this problem down cause I have 5 more like this one to do. Thank you!
from Marth's last line
So x = 2 or x = 1 ...
that should have said
So x = 2 or x = -1
Since he squared both sides, all answers must be verified.
if x=2
LS = √(3-2) = √1 = 1
RS = 2-1 = 1 OK
if x = -1
LS = √(3+1) = √4 = 2
RS = -1 - 1 = -2
so LS is not equal to RS
so the only solution is x = 2
So x = 2 or x = 1 ...
that should have said
So x = 2 or x = -1
Since he squared both sides, all answers must be verified.
if x=2
LS = √(3-2) = √1 = 1
RS = 2-1 = 1 OK
if x = -1
LS = √(3+1) = √4 = 2
RS = -1 - 1 = -2
so LS is not equal to RS
so the only solution is x = 2
2 or 1 or
2 or -1?
annaiiz ceballos said
it is x=2 or x=1 its x=2 or x=-1
2 or -1?
annaiiz ceballos said
it is x=2 or x=1 its x=2 or x=-1
5 answers