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Solve the equation by completing the square. Round to the nearest hundredth. x^2+6x=-7Asked by zacc
solve the equation by completing the square. round to the nearest hundredth.
x^2+10x=18
x^2+10x=18
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First, we need to rearrange the equation so that the constant term is on the right side:
x^2 + 10x - 18 = 0
To complete the square, we need to add and subtract (10/2)^2 = 25 to both sides:
x^2 + 10x + 25 - 25 - 18 = 0
Simplifying and factoring:
(x + 5)^2 - 43 = 0
Adding 43 to both sides:
(x + 5)^2 = 43
Taking the square root:
x + 5 = ±√43
Subtracting 5 from both sides:
x = -5 ± √43
Rounding to the nearest hundredth:
x ≈ -8.32 or x ≈ 2.32
x^2 + 10x - 18 = 0
To complete the square, we need to add and subtract (10/2)^2 = 25 to both sides:
x^2 + 10x + 25 - 25 - 18 = 0
Simplifying and factoring:
(x + 5)^2 - 43 = 0
Adding 43 to both sides:
(x + 5)^2 = 43
Taking the square root:
x + 5 = ±√43
Subtracting 5 from both sides:
x = -5 ± √43
Rounding to the nearest hundredth:
x ≈ -8.32 or x ≈ 2.32
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