Asked by John

Solve the equation by completing the square. Round to the nearest hundredth. x^2+6x=-7
Answered by John
Solve the equation by completing the square. Round to the nearest hundredth.
x^2+6x=-7
Answered by John
Solve the equation by completing the square. Round to the nearest hundredth.
x^2-6x=-7
Answered by John
Solve the equation by completing the square.
x^2-6x+7=0
Answered by John
Solve the equation by completing the square. x^2-6x+7=0
Answered by John
The options are: -1.59 and 4.41, -1.59 and -4.41, 1.59 and -4.41, 1.59 and 4.41
Answered by Bot
First, we need to move the constant to the other side:
x^2 + 6x + 7 = 0

Next, we need to complete the square. To do this, we take half of the coefficient of x, square it, and add it to both sides of the equation:

x^2 + 6x + 9 = 2

The left side can be factored as a perfect square:

(x + 3)^2 = 2

Taking the square root of both sides:

x + 3 = ± √2

Subtracting 3 from both sides:

x = -3 ± √2

Rounding to the nearest hundredth:

x ≈ -3.41, -0.59
Answered by Bot
First, we need to move the constant to the other side:
x^2 + 6x + 7 = 0

Next, we need to complete the square. To do this, we take half of the coefficient of x, square it, and add it to both sides of the equation:

x^2 + 6x + 9 = 2

The left side can be factored as a perfect square:

(x + 3)^2 = 2

Taking the square root of both sides:

x + 3 = ± √2

Subtracting 3 from both sides:

x = -3 ± √2

Rounding to the nearest hundredth:

x ≈ -3.41, -0.59
Answered by Bot
First, we need to move the constant to the other side:
x^2 - 6x + 7 = 0

Next, we need to complete the square. To do this, we take half of the coefficient of x, square it, and add it to both sides of the equation:

x^2 - 6x + 9 = 2

The left side can be factored as a perfect square:

(x - 3)^2 = 2

Taking the square root of both sides:

x - 3 = ± √2

Subtracting 3 from both sides:

x = 3 ± √2

Rounding to the nearest hundredth:

x ≈ 4.41, 1.59
Answered by Bot
To complete the square, we need to add and subtract the square of half the coefficient of x:

x^2 - 6x + (9 - 9) + 7 = 0

The first three terms can be factored as a perfect square:

(x - 3)^2 - 2 = 0

Adding 2 to both sides:

(x - 3)^2 = 2

Taking the square root of both sides:

x - 3 = ± √2

Adding 3 to both sides:

x = 3 ± √2

Therefore, the solution is x = 3 ± √2.
Answered by Bot
To complete the square, we need to add and subtract the square of half the coefficient of x:

x^2 - 6x + (9 - 9) + 7 = 0

The first three terms can be factored as a perfect square:

(x - 3)^2 - 2 = 0

Adding 2 to both sides:

(x - 3)^2 = 2

Taking the square root of both sides:

x - 3 = ± √2

Adding 3 to both sides:

x = 3 ± √2

Therefore, the solution is x = 3 ± √2.
Answered by Bot
Then the solution is 1.59 and 4.41.