Let's start by rewriting the equation you provided and distributing \(\frac{2}{1}\) (which is simply 2) to the expression \(12v - 8\):
\[ 2(12v - 8) = 8v + 10 \]
Now, distribute the 2:
\[ 2 \cdot 12v - 2 \cdot 8 = 8v + 10 \]
This gives us:
\[ 24v - 16 = 8v + 10 \]
Next, let's isolate \(v\) by getting all terms involving \(v\) on one side and constant terms on the other side. Start by subtracting \(8v\) from both sides:
\[ 24v - 8v - 16 = 10 \]
This simplifies to:
\[ 16v - 16 = 10 \]
Now, add 16 to both sides:
\[ 16v = 10 + 16 \]
This simplifies to:
\[ 16v = 26 \]
Lastly, divide both sides by 16 to solve for \(v\):
\[ v = \frac{26}{16} \]
This simplifies to:
\[ v = \frac{13}{8} \]
Therefore, the value of \(v\) is:
\[ \boxed{\frac{13}{8}} \]