solve the absolute value equation

3{2x-2} + 8 = 20

Help (with baby steps please)
I know answer is x=-1 or x=3
( I get the 3 but not the -1)
thank you again

3 answers

Distribute the 3:
6x - 6 + 8 = 20

Subtract 8-6:
6x + 2 = 20

Subtract 2:
6x = 20 -2

6x = 18

Divide 6 on both sides:

(6x/6) = 18/6

x = 3

(x = -1 is not an answer)
3|2x-2| + 8 = 20
3|2x-2| = 12
|2x-2| = 4
2x - 2 = 4 OR 2x-2 = -4
2x = 6 OR 2x = -2
x = 3 OR x = -1

both answers are valid
3|2x-2| + 8 = 20
3|2x-2| = 12
|2x-2| = 4
|x-1| = 2
x-1 = ±2
x = 1±2
x = 3 or -1