Solve for z.

–7(7z–1)=7–4z

1 answer

To solve the equation \(-7(7z - 1) = 7 - 4z\), we start by distributing the \(-7\) on the left side of the equation:

\[ -7 \cdot 7z + (-7) \cdot (-1) = 7 - 4z \] \[ -49z + 7 = 7 - 4z \]

Next, let's move all terms involving \(z\) to one side and constant terms to the other side. We will add \(49z\) to both sides:

\[ 7 = 7 - 4z + 49z \] \[ 7 = 7 + 45z \]

Now, we can subtract \(7\) from both sides:

\[ 7 - 7 = 7 + 45z - 7 \] \[ 0 = 45z \]

To solve for \(z\), divide both sides by \(45\):

\[ z = \frac{0}{45} = 0 \]

Thus, the solution is:

\[ \boxed{0} \]