Solve for yy. Express your answer in simplest radical form if necessary.

Question

y^2 = 32

Answer 1

To solve for \( y \) in the equation \( y^2 = 32 \), we need to take the square root of both sides. Doing this, we get:

\[ y = \pm \sqrt{32} \]

Next, we simplify \( \sqrt{32} \). We can rewrite \( 32 \) as \( 16 \times 2 \) or \( 2^5 \):

\[ \sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2} \]

Therefore, our solutions for \( y \) are:

\[ y = \pm 4\sqrt{2} \]

So, the final answers for \( y \) are:

\[ y = 4\sqrt{2} \quad \text{and} \quad y = -4\sqrt{2} \]