Solve for x

Question

log[1/3](x^(2) + x) - log[1/3] (x^(2) - x) = -1

Steps too please.

so far I tried this and I got 3 = (x+1) / (x-1)

Answer 1

is that base 1/3? lets call that a.

loga(x^2+x) - loga(x^2-x)=-1
loga[(x^2+x)/(x^2-x)]=-1

take the antilog of each side, base a
(x+1)/(x-1)= a^-1

looks like you are correct.