wow, that's a nasty one
do you have a graphing calculator?
if so, graph y = ln(x+1) and
y = x^2 - 8x + 10
zoom in on their intersection point.
I don't have one of those, but with a few trial and error calculations on my oldfashioned machine
I got x = appr 1.38
Solve for x:
ln(x+1)+ 2 = x^2 – 8x + 12
4 answers
can't use a graphing calculator (not allowed). I'm trying to find the area between curves, if that helps.
I ran your equation through a Newton's Method program I have, and I got
x = 1.3795 and
x = 6.83885
If you are going to find area, you might have to integrate ln(x+1)....
hint: take the derivative of
g(x) = (x+1)ln(x+1) and see what you get.
x = 1.3795 and
x = 6.83885
If you are going to find area, you might have to integrate ln(x+1)....
hint: take the derivative of
g(x) = (x+1)ln(x+1) and see what you get.
mckendrick?
1 answer