Solve for x

Question

A. 1/x(6x^3+5x^2)=21
B. X/2+6=-10/x
C. X+6=[x+12]^2

Answer 1

#1
multiply both sides by x
6x^3 + 5x^2 = 21x
x(6x^2+ 5x - 21) = 0
x=0
or
x= -5±√529)/12
= (-5 ± 23)/12 = 3/2 or -7/3

but x ≠ 0 in the original equation, we can't divide by zero

x = 3/2 or x = -7/3

B) multiply each term by 2x
x^2 + 12x = -20
x^2 + 12x + 20 = 0
(x+10(x+2) = 0
x = -10 or x = -2

C) expand it first
x+6 = x^2 + 24x + 144
take over ....

Answer 2

thanks reiny I got all of those correct thanks alot